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8x^2-91x+188=-3x-4
We move all terms to the left:
8x^2-91x+188-(-3x-4)=0
We get rid of parentheses
8x^2-91x+3x+4+188=0
We add all the numbers together, and all the variables
8x^2-88x+192=0
a = 8; b = -88; c = +192;
Δ = b2-4ac
Δ = -882-4·8·192
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-40}{2*8}=\frac{48}{16} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+40}{2*8}=\frac{128}{16} =8 $
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